If f(x), g(x), h(x) are polynomials of degree 4 and ∣∣
∣∣f(x)g(x)h(x)abcpqr∣∣
∣∣=mx4+nx3+rx2+5x+tbe an identity in x, then the value of ∣∣
∣∣f′′′(0)−f′′(0)g′′′(0)−g′′(0)h′′′(0)−h′′(0)abcpqr∣∣
∣∣ is
A
(3n-r)
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B
2(3n-r)
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C
3(3n-r)
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D
3n+r
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Solution
The correct option is B 2(3n-r) LHS = (24mx + 6n) - (12mx2 + 6nx +2r) x = 0 ⇒ 6n - 2r ⇒ 2(3n-r).