If f(x),g(x),h(x) are three polynomials of degree 3, then ϕ(x)=∣∣
∣
∣∣f′(x)g′(x)h′(x)f′′(x)g′′(x)h′′(x)f′′′(x)g′′′(x)h′′′(x)∣∣
∣
∣∣ a polynomial of degree:
A
3
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B
4
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C
5
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D
None of these
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Solution
The correct option is A 3 Writing degrees in the determinant,
∣∣
∣∣222111000∣∣
∣∣
Hence as we expand the determinant, we would have terms with x2×x×λ form, ⇒ϕ(x) would be of 3 degree ⇒(A)