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Question

If f(x) has a derivative at x=a, then limxaxf(a)af(x)xa is equal to

A
f(a)af(a)
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B
af(a)f(a)
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C
f(a)+f(a)
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D
af(a)+f(a)
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Solution

The correct option is A f(a)af(a)
limxxf(a)af(x)xa
Applying L' Hospital Rule
limxf(a).1af(x)1f(a)af(a)

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