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Byju's Answer
Standard XII
Mathematics
Property 5
If fx = ∫1xdt...
Question
If
f
(
x
)
=
∫
x
1
d
t
2
+
t
4
, then
A
f
(
2
)
<
1
3
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B
f
(
2
)
>
1
3
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C
f
(
2
)
1
3
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D
f
(
2
)
>
1
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Solution
The correct option is
A
f
(
2
)
<
1
3
f
′
(
x
)
=
1
2
+
x
4
By LMVT
(
C
)
=
f
(
2
)
−
f
(
1
)
2
−
1
for some
c
ϵ
(1,2)
⇒
f
(
2
)
=
1
2
+
c
4
a
s
f
(
1
)
=
0
⇒
1
<
c
<
2
⇒
3
<
2
+
c
4
<
18
⇒
f
(
2
)
<
1
3
Suggest Corrections
0
Similar questions
Q.
lf
f
(
x
)
a polynomial of degree 2 in
x
such that
f
(
0
)
=
f
(
1
)
=
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f
(
2
)
=
−
3
then
∫
f
(
x
)
x
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−
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d
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=
Q.
Evaluate
∫
f
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x
)
x
3
−
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d
x
, where
f
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x
)
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in
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such that
f
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)
=
f
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=
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f
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=
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Q.
If
∫
f
(
x
)
1
−
x
3
d
x
=
log
∣
∣
∣
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2
+
x
+
1
x
−
1
∣
∣
∣
A
948
√
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t
a
n
−
1
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x
+
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√
3
+
C
then A = ___,
where
f
(
x
)
is a polynomial of second degree in x such that
f
(
0
)
=
f
(
1
)
=
3
f
(
2
)
=
3
.
Q.
When
2
f
3
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f
2
−
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is divided by
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