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Question

If f(x)=dxsin1/2xsin7/2x, then f(π4)f(0)=

A
2.67
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B
2.3
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C
2.4
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D
2.5
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Solution

The correct option is A 2.67
Mistake :cosx must be there instead of sinx
dxsin1/2xcos7/2x=sec4xtan1/2xdx=(tan1/2x+tan3/2x)sec2xdx=2tan1/2x+tan3/2x32+C
f(π4)f(0)=2+23=83=2.67



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