If f(x) is a differentiable function and f(x)−x3 is strictly increasing, then f(x)+x−x2 is
A
increasing
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B
decreasing
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C
not monotonic
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D
not depends on nature of f(x)
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Solution
The correct option is A increasing Let H(x)=f(x)−x3 ⇒H′(x)=f′(x)−3x2>0 ⇒f′(x)>3x2 Let h(x)=f(x)+x−x2 h′(x)=f′(x)+1−2x ⇒h′(x)>3x2−2x+1>0 Hence, h(x) is increasing.