If f(x) is a non-zero polynomial of degree four, having local extreme points at x=−1,0,1; then the set S={x∈R:f(x)=f(0)} Contains exactly:
A
Four irrational numbers
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B
Two irrational and one rational number
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C
Four rational numbers
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D
Two irrational and two rational numbers
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Solution
The correct option is B Two irrational and one rational number f′(x)=λ(x+1)(x−0)(x−1)=λ(x3−x) ⇒f(x)=λ(x44−x22)+μ Now f(x)=f(0) ⇒λ(x44−x22)+μ=μ ⇒x=0,0,±√2 Two irrational and one rational number.