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Question

If f(x) is defined on (1,1) , then the domain of g(x)=f(ex)+f(loge|x|)) is

A
(e,1e)
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B
(0,)
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C
(e,)
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D
R{0}
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Solution

The correct option is A (e,1e)
Since f(x) is defined on (1,1)
1<ex<1,1<loge|x|<1
x(,0) 1e<|x|<e
x(e,1e)(1e,e)
Hence x(e,1e)

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