If f(x) is differential function satisfying 6x∫10f(xt)dt=2x3−3x2+6x+5, then
f(x) is symmetric about x = 1/2
f(x)=0 has no real roots
f(x) = 1/2 has two real roots
f(x) is minimum at x = 1/2
6∫x0f(t)dt=2x3−3x2+6x+5⇒f(x)=x2−x+1
If f(x) is differential function satisfying 6. ∫10f(t)dt=2x3−3x2+6x+5, then