If f(x)=kx-cosx is monotonically increasing for all x∈R, then
K>–1
K<1
K>1
None of these
Explanation for correct option:
Find the value of k:
Given,
f(x)=kx–cosx
Differentiated the given function with respect to x.
f'(x)=k+sinx
Since the function is monotonically increasing for all x∈R,f’(x)>0, so
f'(π/2)>0⇒k+sin(π/2)>0⇒k+1>0⇒k>-1
Hence, the correct option is A.
If f(x)=kx-sinxin monotonically increasing, then