If fx - - 8x-4x-2x - 1-x2- x - 0- exsin x - - x - - - x - 0 - is continuous at x - 0- then the value of - is- fx - - 8x-4x-2x - 1-x2- x - 0- exsin x - - x - - - x - 0 - x - 0 - - - - - - - -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Continuity of a Function

If fx = [ 8x...

Question

If f(x) = ${\begin{matrix} \frac{8^{x} - 4^{x} - 2^{x} + 1}{x^{2}}, & x > 0 e^{x} sin x + π x + λ, & x ⩽ 0 \end{matrix}$ is continuous at x = 0, then the value of λ is

यदि f(x) = ${\begin{matrix} \frac{8^{x} - 4^{x} - 2^{x} + 1}{x^{2}}, & x > 0 e^{x} sin x + π x + λ, & x ⩽ 0 \end{matrix}$ , x = 0 पर सतत है, तब λ का मान है

(log_e4)²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

–log_e2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2(log_e2)²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4log_e2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

f (x)

f (x) \begin{matrix} = \frac{8^{x} - 2^{x}}{k^{x} - 1} f o r x \neq o = 2 x = 0 \end{matrix}} a t x = 0

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} \frac{8^{x} - 4^{x} - 2^{x} + 1^{x}}{x^{2}}, x > 0 e^{x} sin x + π x + λ ln 4, x \leq 0 \end{matrix}

x = 0

λ

f (x)

x = 0

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{e^{\frac{1}{x}}}{1 + e^{\frac{1}{x}}} x \neq 0 0 x = 0 \end{matrix}

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} \frac{8^{x} - 4^{x} - 2^{x} + 1}{x^{2}}, & x > 0 e^{x} sin x + π x + λ ln 4, & x \leq 0 \end{matrix}

x = 0

λ

f (x) = {\begin{matrix} \frac{sin 2 x + log (1 - 3 x)}{2 x}; & 0 < x < \frac{1}{3} k; & x = 0 \end{matrix}

f (x) = {\begin{matrix} \frac{sin 2 x - log (1 - 3 x)}{2 x}; & 0 < x < \frac{1}{3} k; & x = 0 \end{matrix}

Join BYJU'S Learning Program