Question

$Iff\left(x\right)=\{\begin{array}{c}1-x,0\le x\le 2\\ x-1,2\le x\le 4\\ 1,4\le x\le 6\end{array}$
then find,
$f\left(0\right)+f\left(\frac{1}{2}\right)+f\left(1\right)+f\left(\frac{45}{18}\right)$

• A. 1
• B. 2
• C. 3
• D. None of these

Answer 1

The correct option is C 3

$f\left(0\right)=1-0=1,f\left(\frac{1}{2}\right)=1-\frac{1}{2}=\frac{1}{2}=0.5f\left(1\right)=1-1=0,f\left(\frac{45}{18}\right)=2.5-1=1.5$
$\therefore f\left(0\right)+f\left(\frac{1}{2}\right)+f\left(1\right)+f\left(\frac{45}{18}\right)=1+0.5+0+1.5=3$