If f(x)=⎧⎪⎨⎪⎩4x,x<01,x=03x2,x>0 then limx→0f(x) equals
A
0
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B
1
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C
3
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D
does not exist
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Solution
The correct option is C 0 Left hand limit, L−=limx→0−f(x)=4.(0)=0 and Right hand limit, L+=limx→0+f(x)=3.(0)2=0 Hence Required limit is =limx→0f(x)=L+=L−=0