wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If f(x)=ax2b,when0x<12,whenx=1x+1,when1<x2 is continuous at x = 1, then the most suitable value of a, b are

A
a = 2, b = 0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a = 1, b = -1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a = 4, b = 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
All the above
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D All the above
f(1)=2limx1f(x)=ablimx1+f(x)=2ab=2
All the given sets of a, b make f(x) continuous at x =1.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Terms in AP
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon