If f(x)=⎧⎪⎨⎪⎩sin3xx2+x,x≠0λ+2,x=0 is continuous at x=0, then the value of λ is
[2 marks]
A
0
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B
−1
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C
1
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D
3
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Solution
The correct option is C1 For continuity at x=0, we must have f(0)=limx→0f(x)=limx→0sin3xx2+x ⇒f(0)=limx→03x⋅sin3x3xx2+x ⇒f(0)=limx→03xx2+x ⇒f(0)=limx→03x+1 ⇒f(0)=3 ⇒λ+2=3 ∴λ=1