If f(x)={ex−10≤x≤1x+1−{x},1<x<3 and g(x)=x2−ax+b, such that f(x). g(x) is continuous in [0,3) then the values of a and b is
3,2
Clearly f(x) is discontinuous at x = 1 and 2, for f(x) g(x) to be continuous at x = 1 and 2 ; g(1) and g(2) = 0 ⇒ a = 3 and b = 2