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Question

If f(x)=⎪ ⎪ ⎪⎪ ⎪ ⎪sin(a+1)x+2sin xxif x<02,if x=01+bx1x,if x>0 is continuous at x = 0, then find the values of a and b.

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Solution

LHL (at x = 0) : limx0sin(a+1)x+2sin xx=limx0(sin(a+1)x(a+1)x)×(a+1)+2(sin xx)=1×(a+1)+2×1=a+3 [As x0(a+1)x0RHL(at x=0):limx0+1+bx1x=limx0+b×11+bx+1=b2

Also, f(0) = 2

As f(x) is continuous at x = 0 so, a + 3 = 2 = b2 a=1, b=4.


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