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Question

If f(x)=sin(cosx)cosx(π2x)3ifxπ2kifx=π2 is continuous at x=π2, then k=

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Solution

limxπ2sin(cosx)cosx(π2x)3
=limxπ2cos(cosx).(sinx)+sinx3(π2x)2×2
limxπ2cos(cosx).(sin)+(cosx).sin(cosx)+sinx.cos(cosx)sin(cosx).(cosx)sinx6×2×(2)×(2)
=1×1+116×8=1+1+148=348

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