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Byju's Answer
Standard XII
Mathematics
Theorems for Continuity
If fx= sin ...
Question
If
f
(
x
)
=
⎧
⎪
⎨
⎪
⎩
sin
(
cos
x
)
−
cos
x
(
π
−
2
x
)
3
i
f
x
≠
π
2
k
i
f
x
=
π
2
is continuous at
x
=
π
2
, then
k
=
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Solution
lim
x
→
π
2
sin
(
cos
x
)
−
cos
x
(
π
−
2
x
)
3
=
lim
x
→
π
2
cos
(
cos
x
)
.
(
−
sin
x
)
+
sin
x
3
(
π
−
2
x
)
2
×
−
2
lim
x
→
π
2
−
cos
(
cos
x
)
.
(
−
sin
)
+
(
−
cos
x
)
.
−
sin
(
cos
x
)
+
sin
x
.
cos
(
cos
x
)
−
sin
(
cos
x
)
.
(
−
cos
x
)
−
sin
x
−
6
×
2
×
(
−
2
)
×
(
−
2
)
=
−
1
×
−
1
+
1
−
1
−
6
×
8
=
1
+
1
+
1
−
48
=
−
3
48
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0
Similar questions
Q.
f
(
x
)
=
1
−
sin
x
(
π
−
2
x
)
4
.
cos
x
.
(
8
x
3
−
π
3
)
(
x
≠
π
2
)
f
(
π
/
2
)
if
f
(
x
)
is continuous at
x
=
π
/
2
is
−
a
π
2
b
.
Find
b
−
a
Q.
f
(
x
)
=
⎧
⎪ ⎪
⎨
⎪ ⎪
⎩
K
cos
x
π
−
2
x
;
x
≠
π
2
5
;
x
=
π
2
Find the value of K so that the function is continuous at the point
x
=
π
2
.
Q.
If the function
f
(
x
)
=
⎧
⎪
⎨
⎪
⎩
√
2
+
cos
x
−
1
(
π
−
x
)
2
x
≠
π
k
x
=
π
is continuous at
x
=
π
, then
k
equals :
Q.
Find the values of
k
so that the function
f
is continuous at the indicated point:
f
(
x
)
=
⎧
⎪ ⎪
⎨
⎪ ⎪
⎩
k
cos
x
π
−
2
x
,
x
≠
π
2
3
,
x
=
π
2
at
x
=
π
2
Q.
If
f
(
x
)
is continuous on
[
−
π
,
π
]
, where
f
(
x
)
=
⎧
⎪ ⎪
⎨
⎪ ⎪
⎩
−
2
sin
x
,
f
o
r
−
π
≤
−
π
2
α
sin
x
+
β
,
f
o
r
−
π
2
<
x
<
π
2
cos
x
f
o
r
π
2
≤
x
≤
π
then
α
and
β
are
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