If f(x)=⎧⎪⎨⎪⎩x2+2x<03x=0x+2x>0, then which of the following statement(s) is/are false ?
A
f(x) has a local maximum at x=0
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B
f(x) is strictly decreasing on the left of x=0
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C
f′(x) is strictly increasing on the left of x=0
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D
f′(x) is strictly increasing on the right of x=0
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Solution
The correct option is Bf′(x) is strictly increasing on the right of x=0 f(0)=3 limx→0−f(x)=2 limx→0+f(x)=2 Therefore there is a local maximum at x=0 f′(x)=2x for x<0 therefore f(x) is decreasing for x<0 f′′(x)=2 for x<0, hence f′(x) is increasing for x<0 f′(x)=1>0forx>0 therefore f(x) is increasing for x>0 f′(x) is constant for x>0 , hence option D is false