If f(x)=∣∣
∣
∣∣xnsinxcosxn!sinnπ2cosnπ2aa2a3∣∣
∣
∣∣, then the value of dndxn(f(x)) at x=0 for n=2m+1 is
A
dependent on n
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B
0
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C
1
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D
dependent on a
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Solution
The correct option is B0 We have, f(x)=∣∣
∣
∣∣xnsinxcosxn!sinnπ2cosnπ2aa2a3∣∣
∣
∣∣ ⇒dndxn(f(x))=∣∣
∣
∣
∣
∣∣n!sin(nπ2+x)cos(nπ2+x)n!sinnπ2cosnπ2aa2a3∣∣
∣
∣
∣
∣∣ ⇒{dndxn(f(x))}x=0=∣∣
∣
∣
∣∣n!sinnπ2cosnπ2n!sinnπ2cosnπ2aa2a3∣∣
∣
∣
∣∣=0 (Since the two rows are the same.)