CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

One - One function

If f x= x+1...

Question

If $f (x) = {x + 1; 0 \leq x < 2}$ . then find the $fof (x)$ .

Open in App

Solution

$f o f (x) = [f (x) + 1; 0 \leq f (x) \leq 2] = [x + 2; 0 \leq x \leq 1]$

Suggest Corrections

thumbs-up

0

Similar questions

f (x) = \frac{x}{\sqrt{1 - x^{2}}}

(f o f) (x) =

f : R \to R

f (x) = \frac{x - 1}{2}

(f o f) (x)

f (x) = \frac{1 - x}{1 + x}

then the value of

(f o f) (x)

.

f (x) = \frac{a x + b}{c x + d}

(f o f) (x) = x

f (x) = \frac{3 x + 2}{4 x - 3}

x \neq \frac{3}{4}

f o f (x)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Types of Functions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

One - One function

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon