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Byju's Answer
Standard XII
Mathematics
Using Monotonicity to Find the Range of a Function
If fx=lnx2+e/...
Question
If
f
(
x
)
=
l
n
(
x
2
+
e
x
2
+
1
)
, then range of f(x) is
A
(
0
,
1
)
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B
(
0
,
1
]
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C
[
0
,
1
)
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D
{
0
,
1
}
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Solution
The correct option is
B
(
0
,
1
]
f
(
x
)
=
l
n
(
x
2
+
e
x
2
+
1
)
=
l
n
(
x
2
+
1
−
1
+
e
x
2
+
1
)
=
l
n
(
1
+
e
−
1
x
2
+
1
)
Clearly range is (0, 1]
Hence (B) is correct answer
Suggest Corrections
0
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