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Byju's Answer
Standard XII
Mathematics
Monotonically Increasing Functions
If fx=loga ...
Question
If
f
(
x
)
=
log
a
x
is decreasing function, then
a
is
A
<
1
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B
0
<
a
<
1
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C
>
1
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D
>
e
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Solution
The correct option is
B
0
<
a
<
1
f
(
x
)
=
log
a
x
For
x
2
>
x
1
f
(
x
1
)
>
f
(
x
2
)
from the figure
Hence, for
0
<
a
<
1
,
f
(
x
)
=
log
a
x
is decreasing function.
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0
Similar questions
Q.
Prove that the function f(x) = log
a
x is increasing on (0, ∞) if a > 1 and decreasing on (0, ∞), if 0 < a < 1.
Q.
Prove that the function
f
(
x
)
=
l
o
g
a
x
is increasing on
(
0
,
∞
)
if
a
>
1
abd decreasing on (0,x) if 0<a<1.
Q.
I
:
f
(
x
)
=
log
a
x
(
x
>
0
)
is an increasing function if
a
>
1
II
:
f
(
x
)
=
log
a
x
(
x
>
0
)
is a decreasing function if
0
<
a
<
1
Which of the above statements are true ?
Q.
Assertion :Let
f
(
x
)
=
∫
e
x
(
x
−
1
)
(
x
−
2
)
d
x
, then
f
(
x
)
decreases in the interval (1, 2). Reason: If f(x) is decreasing function then
f
′
(
x
)
<
0
Q.
Statement
−
1
:
0
<
x
<
y
⇒
log
a
x
>
log
a
y
, where
a
>
1
.
Statement
−
2
:
When
a
>
1
,
log
a
x
is an increasing function.
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