If fx - loge 1 - x1 - x - gx - 3x - x31 - 3x2 and go ft - gft- then what is go f e - 1e - 1 equal to-

The correct option is B 1 f(e 1e+1)=log_e{1+(e 1e+1)1 (e 1e+1)}=log_e(2e2)=log_ee=1 ∴ gof(e 1e+1)=g(f(e 1e+1))=g(1)=3+11+3=1 ...

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Composite Function

If fx = log...

Question

If $f (x) = {log}_{e} (\frac{1 + x}{1 - x}), g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}$ and $g o f (t) = g (f (t))$ , then what is $g o f (\frac{e - 1}{e + 1})$ equal to?

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Solution

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Similar questions

f (x) = ln \frac{1 + x}{1 - x}

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

f [g (x)]

If $f (x) = l o g (\frac{1 + x}{1 - x})$ and $g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}$ , then f(g(x)) is equal to

f (x) = log (\frac{1 + x}{1 - x})

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

(f (g (x))))

l o g \frac{1 + x}{1 - x}

= \frac{3 x + x^{3}}{1 + 3 x^{2}}

f (x) = l o g (\frac{1 + x}{1 - x})

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

\frac{d}{d x} (f (g (x)))

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