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Question

If f(x)=log(x2+abx(a+b)), then the value of C for which f(c)=0 in [a,b]

A
C=±ab
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B
C=±ab
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C
C=±ba
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D
none of these
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Solution

The correct option is B C=±ab
f(x)=log(x2+abx(a+b))
f(x)=x(a+b)x2+ab⎢ ⎢ ⎢1abx2(a+b)⎥ ⎥ ⎥
=xx2+ab(x2ab)x2
(x2ab)x(x2+ab)=0
x=±ab


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