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Question

If f(x)=logx,g(x)=x3 then f[g(a)]+f[g(b)]=

A
f[g(a)+g(b)]
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B
f[g(ab)]
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C
g[f(ab)]
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D
g[f(a)+f(b)]
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Solution

The correct option is B f[g(ab)]
Given that g(x)=x3. Therefore,
f[g(a)]+f[g(b)]=f(a3)+f(b3).
Since f(x)=logx, we have
f(a3)+fb3=loga3+logb3
=log(a3b3)=log((ab)3)
=f[g(ab)]

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