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Question

If f(x)=sin1x+2tan1x+x2+4x+1, then minimum value of f(x) is
  1. π+2
  2. (π+2)
  3. π2
  4. 2π


Solution

The correct option is B (π+2)
Domain = [-1, 1] and f(x) is increasing function\\
f(x)mini=f(1)=π2+2(π4)+14+1=π2=(π+2)

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