If f(x)=sinx⋅sin2x⋅sin3x, then which of the following is/are true
A
f′(π2)=0
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B
f′(π2)=2
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C
f′′(π12)=17−4√32
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D
f′′(π12)=132
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Solution
The correct option is Cf′′(π12)=17−4√32 f(x)=sinx⋅sin2x⋅sin3x=12sin2x(2sin3xsinx)=12sin2x(cos2x−cos4x)=14(2sin2xcos2x−2cos4xsin2x)f(x)=14(sin4x−sin6x+sin2x)⇒f′(x)=14(2cos2x+4cos4x−6cos6x)⇒f′′(x)=14(−4sin2x−16sin4x+36sin6x)∴f′′(x)=9sin6x−4sin4x−sin2x