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Question

If f(x)=sinxsin2xsin3x, then which of the following is/are true

A
f(π2)=0
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B
f(π2)=2
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C
f(π12)=17432
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D
f(π12)=132
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Solution

The correct option is C f(π12)=17432
f(x)=sinxsin2xsin3x=12sin2x(2sin3xsinx)=12sin2x(cos2xcos4x)=14(2sin2xcos2x2cos4xsin2x)f(x)=14(sin4xsin6x+sin2x)f(x)=14(2cos2x+4cos4x6cos6x)f(x)=14(4sin2x16sin4x+36sin6x)f(x)=9sin6x4sin4xsin2x

So,
f(π2)=2f(π12)=17432

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