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Question

If f(x)=4x2+1|sinx|sinx, then the domain of f(x) is

A
[–2, 0]
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B
(0, 2]
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C
[–2, 2}
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D
[–2, 0)
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Solution

The correct option is D [–2, 0)
f(x)=4x2+1|sinx|sinx
(i) 4x20x242x2
(ii) |sin x| - sin x > 0
when sin x < 0, |sin x| = - sin x -2 sin x>0 sin x<0 if |sin x| = sin x then 0>0 not possible
Domain is [-2,0)

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