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Question

If f(x)=x2+1,g(x)=x+1x2+1 and h(x)=2x3, then find f[h|g(x)|].

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Solution

f(x)=xx2+1
h(x)=2
Hence, irrespective of g(x), h(x) will be constant.
Thus, the required solution is
f(2)=25

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