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Byju's Answer
Standard XII
Mathematics
Theorems for Differentiability
If fx = tan...
Question
If
f
(
x
)
=
tan
x
,
x
∈
[
0
,
π
5
]
then show
π
5
<
f
(
π
5
)
<
2
π
5
.
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Solution
We know that,
When
x
>
0
tan
x
>
x
⇒
tan
(
π
5
)
>
π
5
For upto x slightly greater than
1
we can see that
2
x
>
tan
x
And,
as
π
5
<
1
⇒
2
π
5
>
tan
(
π
5
)
⇒
π
5
<
tan
(
π
5
)
<
2
π
5
.
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0
Similar questions
Q.
Assertion :If
f
(
x
)
=
tan
x
,
x
∈
[
0
,
π
7
]
then
π
7
<
f
(
π
7
)
<
2
π
7
Reason:
sec
2
x
is strictly increasing in
[
0
,
π
7
]
Q.
Let
f
(
x
)
=
1
−
tan
x
4
x
−
π
,
x
≠
π
/
4
,
x
∈
[
0
,
π
2
]
.
If
f
(
x
)
is continuous in
[
0
,
π
2
]
then
f
(
π
4
)
is?
Q.
Let
f
(
x
)
=
1
−
tan
x
4
x
−
π
,
x
≠
π
4
,
x
∈
[
0
,
π
4
]
. lf
f
(
x
)
is continuous in
[
0
,
π
2
]
then
f
(
π
4
)
is:
Q.
If
f
(
x
)
=
sin
x
,
∀
x
∈
[
0
,
π
2
]
,
f
(
x
)
+
f
(
π
−
x
)
=
2
,
∀
x
∈
(
π
2
,
π
]
and
f
(
x
)
=
f
(
2
π
−
x
)
,
∀
x
∈
(
π
,
2
π
]
,
then the area enclosed by
y
=
f
(
x
)
and the
x
-axis is
Q.
If
f
(
x
)
=
sin
x
,
∀
x
∈
[
0
,
π
2
]
,
f
(
x
)
+
f
(
π
−
x
)
=
2
,
∀
x
(
π
2
,
π
]
and
f
(
x
)
=
f
(
2
π
−
x
)
,
∀
x
∈
(
π
,
2
π
)
, then the area enclosed by
y
=
f
(
x
)
and x-axis is
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