If fx-x-1 and gx-x2-1 then f-gfg0-

The correct option is A 2 f(0)=g(0)=1 f(x)+g(x)=(f+g)(x) ⇒1+11.1=2 ...

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Standard XII

Mathematics

Definition of Function

If fx=x+1 a...

Question

If $f (x) = x + 1$ and $g (x) = x^{2} + 1$ then $\frac{f + g}{f g} (0) =$

1

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\frac{1}{4}

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Solution

The correct option is A $2$
$f (0) = g (0) = 1$
$f (x) + g (x) = (f + g) (x)$
$\Rightarrow \frac{1 + 1}{1.1} = 2$

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If f(x)=x+1 and g(x)=x2+1 then f+gfg(0)=

The correct option is A 2f(0)=g(0)=1f(x)+g(x)=(f+g)(x)⇒1+11.1=2

If $f (x) = x + 1$ and $g (x) = x^{2} + 1$ then $\frac{f + g}{f g} (0) =$

The correct option is A $2$
$f (0) = g (0) = 1$
$f (x) + g (x) = (f + g) (x)$
$\Rightarrow \frac{1 + 1}{1.1} = 2$