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Question

If f(x)=(x+1)(x4+x3+2)(x3+4x2+2x+3), then dydxx=1 is

A
0
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B
2
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C
4
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D
8
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Solution

The correct option is D 8
Let, derivative of x4+x3+2=L
and derivative of x3+4x2+2x+3=K
f(x)=(x+1)(L)(x3+4x2+2x+3)+(x+1)(x4+x3+2)(K)+(x4+x3+2)(x3+4x2+2x+3)
f(1)=(21+1)(312+4)=(2)(4)f(1)=8

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