wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If f(x)=(x+1)(x4+x3+2)(x3+4x2+2x+3), then dydxx=1 is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 8
Let, derivative of x4+x3+2=L
and derivative of x3+4x2+2x+3=K
f(x)=(x+1)(L)(x3+4x2+2x+3)+(x+1)(x4+x3+2)(K)+(x4+x3+2)(x3+4x2+2x+3)
f(1)=(21+1)(312+4)=(2)(4)f(1)=8

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon