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Definition of Functions

If fx= x2+1,...

Question

If $f (x) = x^{2} + 1, x \leq 0$
$= 2 x - 1, 0 < x < 5$
$= 4 x + 3, x \geq 5$
then
$\frac{f (- 3) + f (2) + f (5)}{f (1)} =$

A

28

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B

36

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C

26

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D

34

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Solution

The correct option is A $36$
$f (- 3) = 10;$ $f (2) = 3;$ $f (5) = 23$
$f (1) = 1$
$∴ f (- 3) + f (2) + f (5) = 36$

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Similar questions

f (x) = 2 x - 1

x > 1

= x^{2} + 1

- 1 \leq x \leq 1

\frac{f (1) + f (3) + f (0)}{f (2) + f (- 1) + f (\frac{1}{2})}

f (x) = x^{2} - 4 x + 3

, then find the value of

f (2) - f (- 1) + f (\frac{1}{2})

f (x + y) = f (x) \times f (y) \forall x, y \in R

f (5) = 2, f^{'} (0) = 3,

f^{'} (5)

f (x) = ⎧ ⎨ ⎩ \begin{matrix} 3 x + 1, 0 \leq x \leq 2 1 + 9 x, 2 < x < 3 30 + 2 x, x \geq 3 \end{matrix}

f (\frac{5}{2})

Q. If f is a function such that

f (0) = 2, f (1) = 3 a n d f (x + 2) = 2 f (x) - f (x + 1)

for every real x then f(5) is

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