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Question

If f(x)=x2+2x+2;x1
=x2+3x+1;x<1, then the value of f(f(2)) is

A
15
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B
17
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C
22
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D
None of these
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Solution

The correct option is D None of these
f(x)={x2+2x+2;x1x2+3x+1;x<1
f(2)=x2+3x+1=(2)2+3(2)+1=46+1=9f(f(2))=f(9)=(9)2+3(9)+1=8127+1=107 (D) is the correct option.

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