If $f (x) = x^{2} - 3 x - 5$ , then find the value of $f (- 3)$

11

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12

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13

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14

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15

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Solution

The correct option is D $13$
$f (x) = x^{2} - 3 x - 5$
Thus, $f (- 3) = (- 3)^{2} - 3 (- 3) - 5 = 9 + 9 - 5 = 13$

Suggest Corrections

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