If f(x)=x2+6x+a,g(x)=x2+4x+b,h(x)=x2+14x+c and the LCM of f(x), g(x) and h(x) is (x + 8)(x - 2)(x - 6), then the value of a + b +c is
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Solution
f(x)=x2+6x+a g(x)=x2+4x+b h(x)=x2+14x+b LCM of f(x), g(x), h(x) = (x + 8)(x - 2)(x - 6) If we take x+8)(x−2)=x2+6x−16(x−2)(x+6)=x2+4x−12(x+6)(x+8)=x2+14x+48 So comparing we get a = -16, b = -12 and c = 48 ∴ a+b+c = 20.