If $f (x) = x^{2} - 7$ , then find the value $f (a - 3)$ .

a^{2} - 6 a - 16

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a^{2} - 10

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a^{2} + 21

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a^{2} - 6 a + 2

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2 a - 13

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Solution

The correct option is D $a^{2} - 6 a + 2$
Given, $f (x) = x^{2} - 7$
$∴ f (a - 3) = {(a - 3)}^{2} - 7$
$∴ f (a - 3) = a^{2} - 6 a + 9 - 7$
$∴ f (a - 3) = a^{2} - 6 a + 2$

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Similar questions

\frac{a^{2} + 10 a + 21}{a^{2} + 6 a - 7} \times \frac{a^{2} - 1}{a + 3}

Simplify \frac{a^{2} + 10 a + 21}{a^{2} + 6 a - 7} \times \frac{a^{2} - 1}{a + 3}

\frac{(2 a^{2} - a - 3)}{a^{2} + 6 a + 9} \times \frac{a^{2} - 8 a + 16}{(2 a - 3) (a - 4)}

a^{2} + 2 b = 7, b^{2} + 4 c = - 7 a n d c^{2} + 6 a = - 14

(a^{2} + b^{2} + c^{2})

a^{2} + 2 b = 7, b^{2} + 4 c = - 7

c^{2} + 6 a = - 14,

(a^{2} + b^{2} + c^{2})

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