Question

If $f\left(x\right)=x^2+9$ and $g\left(x\right)=24+4x$, what is the value of $\frac{f\left(4\right)}{g(-1)}$?

• A. $0.75$
• B. $0.8$
• C. $1.2$
• D. $1.25$
• E. $1.75$

Answer 1

Answer: (D)

$1.25$

Given,$f\left(x\right)=x^2+9$
$g\left(x\right)=24+4x$
We need to find,$\frac{f\left(4\right)}{g(-1)}$
Putting the values of $f\left(x\right)$ and $g\left(x\right)$
$f\left(4\right)=4^2+9=25$
$g(-1)=24+4(-1)$ $24-4=20$
So, putting the values, we get
$\frac{f\left(4\right)}{g(-1)}$ $=\frac{25}{20}=1.25$