If f(x) = x2 and g(x) = logex, then f(x) + g(x) will be
A
Even function
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B
Odd function
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C
Both
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D
Neither (a) nor (b)
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Solution
The correct option is D Neither (a) nor (b) (x2+logex) would be neither odd nor even since it obeys neither of the rules for even function (f(x) = f(-x)) nor for odd functions (f(x) = -f (-x)).