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Question

If f(x)=x2+1x2 and g(x)=x1x, x ϵ R{1, 0, 1}, and h(x)=f(x)g(x) then the local minimum value of h(x) is

A
22
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B
-3
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C
22
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D
3
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Solution

The correct option is C 22
h(x)=t2+2t, where t=x1x =t+2t
h(x)=12t2=0t=±2
h′′(x)=4t3
Local minimum at t=2
h(2)=2+22=22

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