Question

If $f\left(x\right)=x^2,g\left(x\right)=x^2-5x+6$ then $\frac{g\left(2\right)+g\left(3\right)+g\left(0\right)}{f\left(0\right)+f\left(1\right)+f(-2)}=$

• A. $2$
• B. $1$
• C. $\frac{5}{6}$
• D. $\frac{6}{5}$

Answer 1

The correct option is D $\frac{6}{5}$

$g\left(2\right)=0$
$g\left(3\right)=0$
$g\left(0\right)=6$
$f\left(0\right)=0$
$f\left(1\right)=1$
$f(-2)=4$
On substituting values in the given equation, we get the value as $\frac{6}{5}$