If f(x)=x2+kx+1 is monotonic increasing in [1,2] then the minimum values of k is-
A
4
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B
−4
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C
2
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D
−2
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Solution
The correct option is D−2 f(x)≥0 for monotonically increasing. 2x+k≥0 k≥−2x Now it is increasing in the interval [1,2] Hence k≥−2 and k≥−4 Hence From both we get k≥−2 Hence minimum value of k is −2