If $f (x) = x + 2$ , then $f^{'} [f (x)]$ at $x = 4$ is.

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Solution

The correct option is B $1$
Given, $f (x) = x + 2$
On differentiating, we get $f^{'} (x) = 1$
$∴ f^{'} [f (x)] = f^{'} (x + 2) = 1$
At $x = 4, f^{'} (6) = 1$

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