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Question

If f(x)=x310x2+200x10, then

A
f(x) decreasing in [,10] and increasing in [10,]
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B
f(x) increasing in [α,10] and decreasing in [10,α]
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C
f(x) in increasing throughout real line
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D
None of these
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Solution

The correct option is D f(x) in increasing throughout real line
f(x0=x310x2+200x10f(x)=3x220x+200
But 3x220x+200=3[x2203x+2003]
=3[(x103)2+20031009]
=[(x103)2+5009] > 0 for all x
Therefore, f is increasing throughout real line

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