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B
increasing in (−∞,10] decreasing in (10,∞)
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C
increasing for every value of x
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D
decreasing for every value of x
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Solution
The correct option is C increasing for every value of x f′(x)=3x2−20x+200>0 Now consider g(x)=3x2−20x+200=0 D=400−600 =−200 Hence D<0 f′(x)>0 for all x. Hence f(x)>0 for all xϵR.