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Question

If f(x) = x310x2+200x10, then f(x) is-

A
decreasing in (,10] and increasing in (10,)
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B
increasing in (,10] decreasing in (10,)
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C
increasing for every value of x
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D
decreasing for every value of x
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Solution

The correct option is C increasing for every value of x
f(x)=3x220x+200>0
Now consider
g(x)=3x220x+200=0
D=400600
=200
Hence
D<0
f(x)>0 for all x.
Hence
f(x)>0 for all xϵR.

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