Question

If $f\left(x\right)=x^3-3x^2+3x-1$, then $f\left(\frac{3}{2}\right)=$

Answer 1

Given $f\left(x\right)=x^3-3x^2+3x-1$

$f\left(\frac{3}{2}\right)=f\left(1.5\right)={\left(1.5\right)}^3-3{\left(1.5\right)}^2+3\left(1.5\right)-1$

$f\left(\frac{3}{2}\right)=\frac{27}{8}-\frac{27}{4}+\frac{9}{2}-1=\frac{27-54+36-8}{8}=\frac{1}{8}$