If f(x)=x3+ax2+bx+5sin2x be a decreasing function in R. Then a and b satisfy the condition
A
a2−3b−15>0
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B
a2−3b+15>0
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C
a2−3b−15<0
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D
a2−3b+15<0
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Solution
The correct option is Da2−3b+15<0 f(x)=x3+ax2+bx+5sin2x f′(x)=3x2+2ax+b+5sin2x<0asf(x) is ↓ But sin2x≥−1 ∴3x2+2ax+b−5≤3x2+2ax+b+5sin2x<0 ⇒3x2+2ax+(b−5)<0 ⇒4a2−4∗3(b−5)<0 ⇒a2−3b+15<0