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Question

If f(x)=x3+ax2+bx+5sin2x is a strictly increasing function on the set of real numbers, then a and b must satisfy the relation

A
a23b+150
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B
a23b+200
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C
a23b+250
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D
a23b+300
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Solution

The correct option is A a23b+150
We have f(x)=3x2+2ax+b+5sin2x0
As 1sin2x1,
Hence f(x)=3x2+2ax+b50 xR
So, D0
4a212(b5)0
a23b+150

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