Question

If $f\left(x\right)=x^3-x^2+x+1$, then the value of $\frac{f\left(1\right)+f(-1)}{2}$ will be

• A. 5
• B. 2
• C. 0
• D. -2

Answer 1

The correct option is C 0

Consider the given function.
$f\left(x\right)=x^3-x^2+x+1$
Put $x=1$
$f\left(1\right)=1-1+1+1$
$f\left(1\right)=2$
Put $x=-1$
$f(-1)=-1-1-1+1$
$f(-1)=-2$
Since,
$\frac{f\left(1\right)+f(-1)}{2}$

$=\frac{2-2}{2}$
$=0$
Hence, this is the answer.